SAT数学 Grid-in 练习题（3）

2017年07月21日14:00 来源：互联网: 参与（0）阅读（3631）

摘要：下面是小站SAT频道为大家整理了SAT数学 Grid-in 练习题(3)，供考生们参考，以下是详细内容。

以下是SAT数学 Grid-in 练习题(3)的详细内容，考生可针对文中介绍的方法进行有针对性的备考。最后祝大家在sat考试中取得好成绩!

Question 1: If a§b = 2a - 3b for all real numbers a and b, what is 2(3§2)?

Question 2: A regular polygon has 6 sides. What is the degree measure of the angle, within the polygon, between any two sides?

Question 3: A cubic box 'A' has sides of length a and another cubic box 'B' has sides of length 3a. How many boxes A could fit into a single box B?

Question 4: If a two-sided coin is flipped 4 times, what is the probability that at least one head will show up?

Question 5: What is the value of (2x + 1 - 2x) / (2x - 2x - 1)?

Question 6: Side AB of the ABCD square is 10, AE = ED and BF = FC. What is the ratio between the area of parallelogram BFDE and the area of triangle AEB?

Question 7: If 15% of x is 45, what is 20% of x?

Question 8: Given the | x - 3 | = 5 equation, what is the average of its solutions?

Question 9: In the x, y plane, what is the area of the quadrilateral delimited by the x axis, the y axis, the x = 5 line and the y = -5 line?

Question 10: If the average of x and y is 3, what is the average of x, y and 6?

SAT考试Grid-in练习题3参考答案

Question 1: If a§b = 2a - 3b for all real numbers a and b, what is 2(3§2)?

Answer: 1

Explanation: 2(3§2) = 2(2·3 - 3·2) = 20 = 1

Question 2: A regular polygon has 6 sides. What is the degree measure of the angle, within the polygon, between any two sides?

Answer: 120

Explanation: The sum of all of the angles of a polygon is (n - 2)·180o, where n is the number of sides of the polygon. For a polygon with 6 sides, this is (6 - 2)·180o = 720o

The polygon is regular, so all angles are congruent. The degree measure of the angle, within the polygon, between any two sides is 720o/6 = 120o.

Question 3: A cubic box 'A' has sides of length a and another cubic box 'B' has sides of length 3·a. How many boxes 'A' could fit into a single box 'B'?

Answer: 27

Explanation: The volume of box 'A' is a3 while the volume of box 'B' is (3·a)3.

The number of boxes A that could fit into a box B is the ratio between the volumes of the 2 boxes. This is (3·a)3 / a3 = 27

Question 4: If a two-sided coin is flipped 4 times, what is the probability that at least one head will show up?

Answer: 15/16

Explanation:

p1 = the probability that at least one head will show up when the coin is flipped 4 times

p2 = the probability that no heads will show up when the coin is flipped 4 times

p1 + p2 = 1

The probability that no heads will show up when the coin is flipped 4 times =

the probability that the head will not show up when the coin is flipped the 1st time OR

the head will not show up when the coin is flipped the 2nd time OR

the head will not show up when the coin is flipped the 3rd time OR

the head will not show up when the coin is flipped the 4th time.

The probability that no heads will show up when the coin is flipped 4 times, p2 = (1/2) ·(1/2) ·(1/2) ·(1/2) = 1/16

p1 = 1 - p2 = 1 - (1/16) = 15/16

Question 5: What is the value of (2x + 1 - 2x) / (2x - 2x - 1)?

Answer: 2

Explanation: (2x + 1 - 2x) / (2x - 2x - 1) = 2·(2x - 2x - 1) / (2x - 2x - 1) = 2

Question 6: Side AB of the ABCD square is 10, AE = ED and BF = FC. What is the ratio between the area of parallelogram BFDE and the area of triangle AEB?