SAT数学Problem Solving练习题(19)
- 2017年07月25日14:30 来源:互联网
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Question 19: What is the value of (3x + 1 - 3x) / (3x - 3x - 1)?
(a) 6
(b) 3x
(c) 3x + 1
(d) 3x - 1
(e) 3
Answer: The numerator of the fraction is: 3x + 1 - 3x = 3x·(3 - 1) = 2 · 3x
The denominator of the fraction is: 3x - 3x - 1 = 3x - 1·(3 - 1) = 2 · 3x - 1
We can write the fraction as (2 · 3x) / (2 · 3x - 1) = 3x / 3x - 1 = 3